3y^2+2y=5

Solution for 3y^2+2y=5 equation:

Simplifying
3y2 + 2y = 5

Reorder the terms:
2y + 3y2 = 5

Solving
2y + 3y2 = 5

Solving for variable 'y'.

Reorder the terms:
-5 + 2y + 3y2 = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 2y + 3y2 = 0

Factor a trinomial.
(-5 + -3y)(1 + -1y) = 0

Subproblem 1
Set the factor '(-5 + -3y)' equal to zero and attempt to solve:

Simplifying
-5 + -3y = 0

Solving
-5 + -3y = 0

Move all terms containing y to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -3y = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -3y = 0 + 5
-3y = 0 + 5

Combine like terms: 0 + 5 = 5
-3y = 5

Divide each side by '-3'.
y = -1.666666667

Simplifying
y = -1.666666667
Subproblem 2
Set the factor '(1 + -1y)' equal to zero and attempt to solve:

Simplifying
1 + -1y = 0

Solving
1 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = 0 + -1
-1y = 0 + -1

Combine like terms: 0 + -1 = -1
-1y = -1

Divide each side by '-1'.
y = 1

Simplifying
y = 1
Solution
y = {-1.666666667, 1}